Get out notes from yesterday.. We did not finish last section. And a note sheet for todayno we are not doing this all today! HMWK: Work on HP due this Friday!!! Quiz tomorrow on Unit 8 conversions.

UNIT 8 Day 2 More Conversions and Two step Conversions STP problems Mole/Gram Conversions 1. 2.

3. 25 g NaCl = _________ moles 3.2 moles of MgCO3 = _______ grams .33 moles MgCl2 = _____________ grams Mole/Gram Conversions 1.

2. 25 g NaCl = _________ moles 0.43 mol 3.2 moles of MgCO3 = _______ grams 269.8 g 3.

.33 moles MgCl2 = _____________ grams 31.42 g Mole/Volume Conversions Avogadros Hypothesis: equal volumes of gases at the same temperature and pressure contain equal numbers of particles. At STP, 1 mole of any gas occupies a volume of 22.4 L. Ex. 5.4 moles CH4 x 22.4 L = 120.96 L CH4

1 mol Mole Ratios The mole ratio is indicated by the coefficients in the balanced equation. 2Mg + O2 2MgO How many moles of each substance? 2 moles Mg 1 mole O2 2 moles of MgO

Mole Ratio N2 + 3 H2 2 NH3 1. Balance the equation 2. What is the mole ratio of nitrogen gas to ammonia? 1: 3 : 2 3. If 2 moles of Nitrogen react with an excess of hydrogen, how many moles of NH3 will be produced? 4 moles of NH3

Mole Ratio N2 + H2 NH3 1. Balance the equation 2. What is the mole ratio of nitrogen gas to ammonia? 3. If 2 moles of Nitrogen react with an excess of hydrogen, how many moles of NH3 will be produced?

Mole Ratio How many moles of KClO3 must decompose in order to produce 9 moles of oxygen gas? 2KClO3 3O2 + 2KCl Ratio = 2:3:2 2 x 3 = 6 moles TODAY. 1. Review of Chalk Lab

2. Quiz on Molar Mass and molar conversions. 3. Stoichiometry Video 4. Two step conversion notes HMWK: HP part 5 due tomorrow- yellow sheet and Share with me your Googledoc or bring in your showboard for me to look at 2 step conversion problems

Determine the mass of lithium hydroxide produced when 0.38 g of lithium nitride reacts with water according to the following equation: Li3N + 3H2O NH3 + 3LiOH Step 1: Determine given and unknown. Given: mass of Li3N = 0.38 g Unknown: Mass of LiOH Step 2: Start with givens, and add conversions to get to unknown. Step 3: Solve by canceling out units and multiplying/dividing 2 step conversion cont. Determine the mass of lithium hydroxide produced when 0.38 g of

lithium nitride reacts with water according to the following equation: Li3N + 3H2O NH3 + 3LiOH 0.38 g Li3N x 1 mol Li3N x 3 mol LiOH x 23.95 g LiOH = 0.78g 34.83 gLi3N 1 mol Li3N 1 mol LiOH LiOH 2 step conversion Practice Find the mass of sugar (C6H12O6) required to produce 1.82 L of Carbon Dioxide gas at STP from the reaction described by the

following equation: C6H12O6 2C2H6O + 2CO2 Start with what you know You got to get from 1.82 L CO2 to grams of sugar. You will need to find the Molar mass of sugar = 180.156g Molar mass of Carbon Dioxide = 44.01 g

2 step conversion Practice Find the mass of sugar (C6H12O6) required to produce 1.82 L of Carbon Dioxide gas at STP from the reaction described by the following equation: C6H12O6 2C2H6O + 2CO2 Now.. Set up conversions to get what you want on the top of the equation L Carbon Dioxide X mole CO2 X mole Sugar X g sugar = _____________ ________ _________ _______

1 L CO2 mole CO2 mole sugar 2 step conversion Practice Find the mass of sugar (C6H12O6) required to produce 1.82 L of Carbon Dioxide gas at STP from the reaction described by the following equation: C6H12O6 2C2H6O + 2CO2 Now.. Set up conversions to get what you want on the top of the

equation 1.82 L CO2 X 1 m CO2 X 1 m C6H12O6 X 180.156 g C6H12O6 = 7.32 gC6H12O6 _____________ ________ _________ _______ 1 22.4 L CO2 2 m CO2 1 m sugar 2 step conversion Practice

How many liters of Oxygen at STP are needed to react with 5.2 x 1022 molecules of hydrogen sulfide? 2H2S + 3O2 2SO2 + 2H2O Start with what you know and figure out what you want to know and what units it needs to be in! Molecules of H2S and you want L of O2 both on top 2 step conversion Practice How many liters of Oxygen at STP are needed to react with 5.2 x 1022 molecules of hydrogen sulfide?

2H2S + 3O2 2SO2 + 2H2O 1.93 L Oxygen How many grams of Aluminum Carbonate are needed to produce 4.5 grams of Aluminum Oxide in the following reaction? Al2(CO3)3 Al2O3 + 3CO2 Youve got to go from Grams Al2 O3 to g Al2 (CO3 )3